-v^2=-23-132

Solution for -v^2=-23-132 equation:

-v^2=-23-132

We move all terms to the left:

-v^2-(-23-132)=0

We add all the numbers together, and all the variables

-v^2-(-155)=0

We add all the numbers together, and all the variables

-1v^2+155=0

a = -1; b = 0; c = +155;
Δ = b2-4ac
Δ = 02-4·(-1)·155
Δ = 620
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{620}=\sqrt{4*155}=\sqrt{4}*\sqrt{155}=2\sqrt{155}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{155}}{2*-1}=\frac{0-2\sqrt{155}}{-2}
=-\frac{2\sqrt{155}}{-2}
=-\frac{\sqrt{155}}{-1}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{155}}{2*-1}=\frac{0+2\sqrt{155}}{-2}
=\frac{2\sqrt{155}}{-2}
=\frac{\sqrt{155}}{-1}
$